How do you divide #(6x^3 + 10x^2 + x + 8) / (2x^2 + 1)#?

1 Answer
Alan P.
Nov 14, 2015

#(6x^3+10x^2+x+8)/(2x^2+1) = 3x+5# with remainder #(-2x+3)#

Explanation:

Using polynomial long division:
#{: (,,3x,+5,,), (,,"----","----","----","----"), (2x^2+1,")",6x^3,+10x^2,+x,+8), (,,6x^3,,+3x,), (,,"----","----","----","----"), (,,,10x^2,-2x,+8), (,,,10x^2,,+5), (,,,"----","----","----"), (,,,,-2x,+3) :}#

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