How do you divide $\frac{3 x^{3} + 4 x^{2} + 2 x + 5}{x - 4}$ $(3x^3+4x^2+2x+5)/(x-4)$ ?

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How do you divide $\frac{3 x^{3} + 4 x^{2} + 2 x + 5}{x - 4}$ $(3x^3+4x^2+2x+5)/(x-4)$ ?

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Answer 1 · 2018-07-10T07:32:46

The remainder is $269$ $269$ and the quotient is $= 3 x^{2} + 16 x + 66$ $=3x^2+16x+66$

Explanation:

Let's perform the synthetic division

$a a a a$ $color(white)(aaaa)$ $4$ $4$ $∣$ $|$ $a a a a$ $color(white)(aaaa)$ $3$ $3$ $a a a a$ $color(white)(aaaa)$ $4$ $4$ $a a a a a a$ $color(white)(aaaaaa)$ $2$ $2$ $a a a a a a a$ $color(white)(aaaaaaa)$ $5$ $5$

$a a a a a$ $color(white)(aaaaa)$ $∣$ $|$ $a a a a$ $color(white)(aaaa)$ $a a a a a$ $color(white)(aaaaa)$ $12$ $12$ $a a a a a$ $color(white)(aaaaa)$ $64$ $64$ $a a a a a$ $color(white)(aaaaa)$ $264$ $264$

$a a a a a a a a a$ $color(white)(aaaaaaaaa)$ _________

$a a a a a$ $color(white)(aaaaa)$ $∣$ $|$ $a a a a$ $color(white)(aaaa)$ $3$ $3$ $a a a a$ $color(white)(aaaa)$ $16$ $16$ $a a a a a$ $color(white)(aaaaa)$ $66$ $66$ $a a a a a a$ $color(white)(aaaaaa)$ $269$ $color(red)(269)$

The remainder is $269$ $269$ and the quotient is $= 3 x^{2} + 16 x + 66$ $=3x^2+16x+66$

$\frac{3 x^{3} + 4 x^{2} + 2 x + 5}{x - 4} = (3 x^{2} + 16 x + 66) + \frac{269}{x - 4}$ $(3x^3+4x^2+2x+5)/(x-4)=(3x^2+16x+66)+(269)/(x-4)$

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How do you divide $\frac{3 x^{3} + 4 x^{2} + 2 x + 5}{x - 4}$ $(3x^3+4x^2+2x+5)/(x-4)$ ?

1 Answer

Explanation:

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How do you divide (3x^3+4x^2+2x+5)/(x-4)3x3+4x2+2x+5x−4(3x^3+4x^2+2x+5)/(x-4) ?

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Explanation:

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How do you divide $\frac{3 x^{3} + 4 x^{2} + 2 x + 5}{x - 4}$ $(3x^3+4x^2+2x+5)/(x-4)$ ?