How do you divide $(6x^3-16x^2+17x-6) / (3x-2)$ ?

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Answer 1 · 2018-05-07T06:05:24

$(6x^3-16x^2+17x-6)/(3x-2)=2x^2-4x+3$

Use long division method.

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How do you divide (6x^3-16x^2+17x-6) / (3x-2)(6x^3-16x^2+17x-6) / (3x-2)?