How do you divide $\frac{6 x^{4} + 4 x^{3} - 12 x^{2} - 7 x - 7}{x - 2}$ $(6x^4+4x^3-12x^2-7x-7)/(x-2)$ ?

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Answer 1 · 2018-01-11T12:53:19

$6 x^{3} + 16 x^{2} + 20 x + 33 + \frac{59}{x - 2}$ $color(blue)(6x^3 + 16x^2 + 20x + 33 + 59/(x-2))$

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How do you divide 6x4+4x3−12x2−7x−7x−2(6x^4+4x^3-12x^2-7x-7)/(x-2) ?