Question

How do you divide `(s^2-3s)/(s^2-s-6) div (s-6)/(s+2)`?

Answer 1

`= ((s^2-3s)/(s^2-s-6))/((s-6)/(s+2))`

`= ((s^2-3s)(s+2))/((s^2-s-6)(s-6))`

`= ((s^2-3s)(s+2))/((s-3)(s+2)(s-6))`

`= ((s^2-3s)cancel((s+2)))/((s-3)cancel((s+2))(s-6))`

`= ((s^2-3s))/((s-3)(s-6))`

`= ((s^2-3s))/((s^2-9s+18))`