How do you divide #(x^2+12x-18)/(x-3)#?

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Answer 1 · 2018-03-08T00:59:39

#x + 9#

#x-3# divided into #x^2+12x-18#

First part of answer is #x#

#x-3# times #x# is #x^2-3x#

Subtract from #x^2+12x-18# to get #9x-18#

Second part will then be #9#

#x-3# times #9# is #9x-18#

So answer is #x+9#