How do you divide #(x^2 + 2x + 3)/(x-1)#?

1 Answer
Nov 4, 2015

As an alternative to the previous answer (since for me, at least it isn't clear how the initial line factors were derived)
you could try polynomial long division or synthetic division.


Polynomial long division for #(x^2+2x+3) div (x-1)# would look something like:
#{: (,,x,+3,), (,,"-----","-----","-----"), (x-1,")",x^2,+2x,+3), (,,x^2,-x,), (,,"-----","-----",), (,,,3x,+3), (,,,3x,-3), (,,,"-----","-----"), (,,,,6) :}#