How do you divide $( x^3+3x^2+4x+12 )/(x^2+2x)$ ?

Question

2112 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-30T14:48:02

The remainder is $=2x+12$ and the quotient is $=x+1$

Perform a long division

$color(white)(aaaa)$ $x^3+3x^2+4x+12$ $color(white)(aaaa)$ $|$ $x^2+2x$

$color(white)(aaaa)$ $x^3+2x^2$ $color(white)(aaaaaaaaaaaaa)$ $|$ $x+1$

$color(white)(aaaaa)$ $0+x^2+4x$

$color(white)(aaaaaaaa)$ $x^2+2x$

$color(white)(aaaaaaaaa)$ $0+2x+12$

The remainder is $=2x+12$ and the quotient is $=x+1$

$(x^3+3x^2+4x+12)/(x^2+2x)=(x+1)+(2x+12)/(x^2+2x)$

How do you divide ( x^3+3x^2+4x+12 )/(x^2+2x)( x^3+3x^2+4x+12 )/(x^2+2x)?