How do you divide $\frac{x^{3} - 7 x - 6}{x + 1}$ $(x^3-7x-6) / (x+1)$ ?

Question

How do you divide $\frac{x^{3} - 7 x - 6}{x + 1}$ $(x^3-7x-6) / (x+1)$ ?

2 Answers

Impact of this question

10110 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-01T07:57:31

The quotient is $= x^{2} - x - 6$ $=x^2-x-6$ and the remainder is $= 0$ $=0$

Explanation:

Perform a long division

$a a a a$ $color(white)(aaaa)$ $x^{3} + 0 x^{2} - 7 x - 6$ $x^3+0x^2-7x-6$ $a a a a$ $color(white)(aaaa)$ $∣$ $|$ $x + 1$ $x+1$

$a a a a$ $color(white)(aaaa)$ $x^{3} + x^{2}$ $x^3+x^2$ $a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $∣$ $|$ $x^{2} - x - 6$ $x^2-x-6$

$a a a a a$ $color(white)(aaaaa)$ $0 - x^{2} - 7 x$ $0-x^2-7x$

$a a a a a a a$ $color(white)(aaaaaaa)$ $- x^{2} - x$ $-x^2-x$

$a a a a a a a$ $color(white)(aaaaaaa)$ $- 0 - 6 x - 6$ $-0-6x-6$

$a a a a a a a a a a a$ $color(white)(aaaaaaaaaaa)$ $- 6 x - 6$ $-6x-6$

$a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaa)$ $- 0 - 0$ $-0-0$

The quotient is $= x^{2} - x - 6$ $=x^2-x-6$ and the remainder is $= 0$ $=0$

$\frac{x^{3} + 0 x^{2} - 7 x - 6}{x + 1} = x^{2} - x - 6$ $(x^3+0x^2-7x-6)/(x+1)=x^2-x-6$

Answer 2 · 2018-07-01T10:38:36

$x^{2} - x - 6$ $x^2-x-6$

Explanation:

Given: $\frac{x^{3} - 7 x - 6}{x + 1}$ $(x^3-7x-6)/(x+1)$

Using place keepers of no value. Example: $0 x^{2}$ $0x^2$

$ddddd.ddddd.d x^{3} + 0 x^{2} - 7 x - 6$ $color(white)("ddddd.ddddd.d")x^3+0x^2-7x-6$
$color(red)(+x^2)(x+1) ->ul(x^3+x^2 larr" Subtract")$
$color(white)("dddddddddddd.")0 -x^2-7x-6$
$color(red)(-x)(x+1)->color(white)("dd.")ul(-x^2-x larr" Subtract")$
$color(white)("dddddddddddddddd")0-6x-6$
$color(red)(-6)(x+1)->color(white)("dddddd.")ul(-6x-6larr" Subtract")$
$color(white)("dddddddddddddddddddd")0+0 larr" Remainder"$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$(x^3-7x-6)/(x+1)=color(red)(x^2-x-6)$

Science

Math

Humanities

... and beyond

How do you divide $\frac{x^{3} - 7 x - 6}{x + 1}$ $(x^3-7x-6) / (x+1)$ ?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you divide (x^3-7x-6) / (x+1)x3−7x−6x+1(x^3-7x-6) / (x+1)?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you divide $\frac{x^{3} - 7 x - 6}{x + 1}$ $(x^3-7x-6) / (x+1)$ ?