How do you divide $\frac{x^{3} - 8 x^{2} - 6}{x - 2}$ $(x^3-8x^2-6) / (x-2)$ ?

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How do you divide $\frac{x^{3} - 8 x^{2} - 6}{x - 2}$ $(x^3-8x^2-6) / (x-2)$ ?

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Answer 1 · 2018-06-24T12:07:30

The quotient is $= x^{2} - 6 x - 12$ $=x^2-6x-12$ and the remainder is $- 30$ $-30$

Explanation:

Perform a long division

$a a a a$ $color(white)(aaaa)$ $x^{3} - 8 x^{2} + 0 x - 6$ $x^3-8x^2+0x-6$ $a a a a$ $color(white)(aaaa)$ $∣$ $|$ $x - 2$ $x-2$

$a a a a$ $color(white)(aaaa)$ $x^{3} - 2 x^{2}$ $x^3-2x^2$ $a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaa)$ $∣$ $|$ $x^{2} - 6 x - 12$ $x^2-6x-12$

$a a a a$ $color(white)(aaaa)$ $0 - 6 x^{2} + 0 x$ $0-6x^2+0x$

$a a a a a a$ $color(white)(aaaaaa)$ $- 6 x^{2} + 12 x$ $-6x^2+12x$

$a a a a a a a a a$ $color(white)(aaaaaaaaa)$ $0 - 12 x - 6$ $0-12x-6$

$a a a a a a a a a a a$ $color(white)(aaaaaaaaaaa)$ $- 12 x + 24$ $-12x+24$

$a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaa)$ $0 - 30$ $0-30$

The quotient is $= x^{2} - 6 x - 12$ $=x^2-6x-12$ and the remainder is $- 30$ $-30$

$\frac{x^{3} - 8 x^{2} - 6}{x - 2} = x^{2} - 6 x - 12 - \frac{30}{x - 2}$ $(x^3-8x^2-6)/(x-2)=x^2-6x-12-30/(x-2)$

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How do you divide $\frac{x^{3} - 8 x^{2} - 6}{x - 2}$ $(x^3-8x^2-6) / (x-2)$ ?

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Explanation:

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How do you divide (x^3-8x^2-6) / (x-2)x3−8x2−6x−2(x^3-8x^2-6) / (x-2)?

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How do you divide $\frac{x^{3} - 8 x^{2} - 6}{x - 2}$ $(x^3-8x^2-6) / (x-2)$ ?