How do you divide $\frac{x^{3} - 8 x + 8 x^{2} - 16}{x^{2} - 4}$ $(x^3-8x+8x^2-16) / (x^2-4)$ ?

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Answer 1 · 2018-07-23T23:19:13

$x + 8 + \frac{- 4 x + 16}{x^{2} - 4}$ $x+8 + (-4x+16)/(x^2-4)$

To divide this, use polynomial long division:

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Hope this helps!

How do you divide x3−8x+8x2−16x2−4(x^3-8x+8x^2-16) / (x^2-4) ?