Question

How do you divide `(-x^3-x^2+9x-3)/(x-3)`?

Answer 1

`-x^2 + 2x +1`

Explanation:

You write the answer using everything you know. The division of a degree 3 by a degree one polynomial will be degree two. So you write
`-x^3 - x^2 + 9x -3 = (x-3)(-x^2 +1 + ax)`
This gives you
`a - 3= -1`
`a=2`