How do you divide $\frac{- x^{4} - 3 x^{3} - 2 x^{2} + 7 x + 3}{x^{2} + 3}$ $(-x^4-3x^3-2x^2+7x+3)/(x^2+3)$ ?

Question

How do you divide $\frac{- x^{4} - 3 x^{3} - 2 x^{2} + 7 x + 3}{x^{2} + 3}$ $(-x^4-3x^3-2x^2+7x+3)/(x^2+3)$ ?

1 Answer

Impact of this question

1998 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-25T14:01:55

$- x^{2} - 3 x + 1 + \frac{16 x}{x^{2} + 3}$ $-x^2-3x+1+(16x)/(x^2+3)$

Explanation:

Using place keepers of zero value. Example: $0 x^{3}$ $0x^3$

$dddddddddddddd + x^{4} - 3 x^{3} - 2 x^{2} + 7 x + 3$ $color(white)("dddddddddddddd")+x^4-3x^3-2x^2+7x+3$
$color(magenta)(-x^2)(x^2+3)->color(white)("d") ul(-x^4+0x^3-3x^2larr" Subtract")$
$color(white)("dddddddddddddddd")0 -3x^3+x^2+7x+3$
$color(magenta)(-3x)(x^2+3) -> color(white)("dddd")ul(-3x^3+0x^2-9xlarr" Subtract")$
$color(white)("ddddddddddddddddddddd")0+x^2+16x+3$
$color(magenta)(+1)(x^2+3)->color(white)("dddddddddddd")ul(x^2+color(white)("..")0x+3larr" Subtract")$
$color(magenta)("Remainder "->color(white)("dddddddddddd.")0+16x+0)$

$color(white)()$

$-x^2-3x+1+(16x)/(x^2+3)$

Science

Math

Humanities

... and beyond

How do you divide $\frac{- x^{4} - 3 x^{3} - 2 x^{2} + 7 x + 3}{x^{2} + 3}$ $(-x^4-3x^3-2x^2+7x+3)/(x^2+3)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you divide (-x^4-3x^3-2x^2+7x+3)/(x^2+3) −x4−3x3−2x2+7x+3x2+3(-x^4-3x^3-2x^2+7x+3)/(x^2+3) ?

1 Answer

Explanation:

Related questions

Impact of this question

How do you divide $\frac{- x^{4} - 3 x^{3} - 2 x^{2} + 7 x + 3}{x^{2} + 3}$ $(-x^4-3x^3-2x^2+7x+3)/(x^2+3)$ ?