How do you divide #( -x^4 + 3x^3 + 9x^2 +4x)/(2x^2-3x)#?
Trigonometry long division gives quotient of
This can be simplified a bit by first taking out common factors. After that you need to do the trigonometry version of long division.
Divide the first element by the first element of the divisor:
Multiply this result by the divisor:
Then subtract this from the dividend:
Repeat this process with the remaining dividend:
And repeat again
The quotient is then the sum of the factors in bold and the remainder is