How do you divide $\frac{- x^{4} - 4 x^{3} - 3 x^{2} - 6 x - 2}{x^{2} + 4}$ $(-x^4-4x^3-3x^2-6x-2)/(x^2+4)$ ?

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How do you divide $\frac{- x^{4} - 4 x^{3} - 3 x^{2} - 6 x - 2}{x^{2} + 4}$ $(-x^4-4x^3-3x^2-6x-2)/(x^2+4)$ ?

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Answer 1 · 2018-02-06T17:48:14

If you go to Topics (https://socratic.org/algebra/topics) and click on the subgroup as listed above (currently within group no 12) you will find lots of examples. There are some different approaches. Have a look at some of mine

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How do you divide $\frac{- x^{4} - 4 x^{3} - 3 x^{2} - 6 x - 2}{x^{2} + 4}$ $(-x^4-4x^3-3x^2-6x-2)/(x^2+4)$ ?

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How do you divide (-x^4-4x^3-3x^2-6x-2)/(x^2+4) −x4−4x3−3x2−6x−2x2+4(-x^4-4x^3-3x^2-6x-2)/(x^2+4) ?

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How do you divide $\frac{- x^{4} - 4 x^{3} - 3 x^{2} - 6 x - 2}{x^{2} + 4}$ $(-x^4-4x^3-3x^2-6x-2)/(x^2+4)$ ?