How do you divide x−5x2+10+x3x+2?
1 Answer
Jul 14, 2018
Explanation:
one way is to use the divisor as a factor in the numerator
consider the rearranged numerator
x3−5x2+x+10
=x2(x+2)−2x2−5x2+x+10
=x2(x+2)−7x(x+2)+14x+x+10
=x2(x+2)−7x(x+2)+15(x+2)−30+10
=x2(x+2)−7x(x+2)+15(x+2)−20
quotient =x2−7x+15, remainder =−20
x−5x2+10+x3x+2=x2−7x+15−20x+2