How do you divide x5x2+10+x3x+2?

1 Answer
Jul 14, 2018

x27x+1520x+2

Explanation:

one way is to use the divisor as a factor in the numerator

consider the rearranged numerator

x35x2+x+10

=x2(x+2)2x25x2+x+10

=x2(x+2)7x(x+2)+14x+x+10

=x2(x+2)7x(x+2)+15(x+2)30+10

=x2(x+2)7x(x+2)+15(x+2)20

quotient =x27x+15, remainder =20

x5x2+10+x3x+2=x27x+1520x+2