Question

How do you draw a right triangle with a hypotenuse of `sqrt72` units?

Answer 1

Draw the arms of a `90°` angle with a length of `6` units and the hypotenuse will have a length of `sqrt72`

Explanation:

Find two square numbers which add up to `72`

According to Pythagoras' Theorem:

`a^2 + b^2 = c^2`

One possibility of such a right-angled triangle is an isosceles right -angled triangle with equal sides of `6` units.

The length of the hypotenuse can be calculated as:

`x^2 = 6^2 + 6^2`

`x^2 = 36+36`

`x^2 =72`

`x = sqrt72`

So, if you draw the arms of a `90°` angle with a length of `6` units, the hypotenuse will have a length of `sqrt72`