How do you draw a right triangle with a hypotenuse of #sqrt72# units?

1 Answer
Jun 1, 2017

Answer:

Draw the arms of a #90°# angle with a length of #6# units and the hypotenuse will have a length of #sqrt72#

Explanation:

Find two square numbers which add up to #72#

According to Pythagoras' Theorem:

#a^2 + b^2 = c^2#

One possibility of such a right-angled triangle is an isosceles right -angled triangle with equal sides of #6# units.

The length of the hypotenuse can be calculated as:

#x^2 = 6^2 + 6^2#

#x^2 = 36+36#

#x^2 =72#

#x = sqrt72#

So, if you draw the arms of a #90°# angle with a length of #6# units, the hypotenuse will have a length of #sqrt72#