# How do you draw a right triangle with a hypotenuse of sqrt72 units?

Jun 1, 2017

Draw the arms of a 90° angle with a length of $6$ units and the hypotenuse will have a length of $\sqrt{72}$

#### Explanation:

Find two square numbers which add up to $72$

According to Pythagoras' Theorem:

${a}^{2} + {b}^{2} = {c}^{2}$

One possibility of such a right-angled triangle is an isosceles right -angled triangle with equal sides of $6$ units.

The length of the hypotenuse can be calculated as:

${x}^{2} = {6}^{2} + {6}^{2}$

${x}^{2} = 36 + 36$

${x}^{2} = 72$

$x = \sqrt{72}$

So, if you draw the arms of a 90° angle with a length of $6$ units, the hypotenuse will have a length of $\sqrt{72}$