How do you evaluate $- 1 - {cos}^{2} (74) - {sin}^{2} (74)$ $-1 - cos^2(74) - sin^2 (74)$ ?

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Answer 1 · 2016-07-01T14:25:14

Factor out $- 1$ $-1$ :

$= - (1 + {cos}^{2} (74^{\circ}) + {sin}^{2} (74^{\circ}))$ $=-(1 +cos^2(74^@) + sin^2(74^@))$

Recall the Pythagorean identity ${cos}^{2} x + {sin}^{2} x = 1$ $cos^2x + sin^2x = 1$ .

$= - (1 + 1)$ $=-(1 + 1)$

$= - 2$ $=-2$

Hopefully this helps!

How do you evaluate −1−cos2(74)−sin2(74)-1 - cos^2(74) - sin^2 (74)?