How do you evaluate # -5/21 + 11/21#?

1 Answer
EZ as pi
Jun 19, 2016

#6/21 = 2/7#

Explanation:

It is probably easier to do if the terms are written in a different orde. As this is addition we may do that.
#11/21-5/21#

The denominators are already the same, so just subtract the numerators to get

#(11-5)/21 = 6/21#

In simplest form
#6/21 = 2/7#

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