How do you evaluate #(- 6- - 6) ^ { 3} + 4#?

2 Answers
Oct 17, 2017

Answer:

#4#

Explanation:

Focus on the parenthesis first. We have

#-6--6# which is simplified to #-6+6# which is just #0#

So our expression is now

#(0)^3+4#

We now evaluate

#0^3+4#

#=0+4#

#=4#

Oct 17, 2017

Answer:

The answer is #4#.

Explanation:

Begin by simplifying within the parentheses.

#(-6-(-6))^3+4 = 0^3+4# because #-6-(-6)=-6+6=0#

#0^3=0#, so #0^3+4 = 4#

The answer is #4#.