How do you evaluate #7 6/7 +4 5/7#?

1 Answer
Mar 31, 2018

Answer:

#12 4/7#

Explanation:

#"note that "7 6/7=7+6/7#

#"and "4 5/7=4+5/7#

#rArr7 6/7+4 5/7#

#=color(red)(7)+6/7color(red)(+4)+5/7#

#=(color(red)(7+4))+6/7+5/7#

#"since fractions have a "color(blue)"common denominator"#
#"add the numerators leaving the denominator"#

#=11+(6+5)/7#

#=11+11/7=11+1 4/7=12+4/7#