How do you evaluate #7 6/7 +4 5/7#?
1 Answer
Mar 31, 2018
Explanation:
#"note that "7 6/7=7+6/7#
#"and "4 5/7=4+5/7#
#rArr7 6/7+4 5/7#
#=color(red)(7)+6/7color(red)(+4)+5/7#
#=(color(red)(7+4))+6/7+5/7#
#"since fractions have a "color(blue)"common denominator"#
#"add the numerators leaving the denominator"#
#=11+(6+5)/7#
#=11+11/7=11+1 4/7=12+4/7#
