Question

How do you evaluate `log_18(9) + log_18(2)`?

Answer 1

`1`

Explanation:

Using the `color(blue)"laws of logarithms"`

`color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(logx+logy=log(xy)" and " log_b b=1)color(white)(2/2)|)))`

`rArrlog_(18)9+log_(18)2=log_(18)18=1`

Answer 2

The answer is `log_18 (9)+log_18 (2)` `=1`.

Explanation:

`log_18 (9)+log_18 (2)`
`=log_18 (9*2)`
`=log_18 (18)`
`=log18/log18`
`=1`. (answer).