# How do you evaluate #log_18(9) + log_18(2)#?

##### 2 Answers

Oct 29, 2016

#### Explanation:

Using the

#color(blue)"laws of logarithms"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(logx+logy=log(xy)" and " log_b b=1)color(white)(2/2)|)))#

#rArrlog_(18)9+log_(18)2=log_(18)18=1#

Oct 29, 2016

The answer is

#### Explanation: