How do you evaluate #log_3 81 #?

1 Answer
Nov 11, 2015

Answer:

The answer is #4#.

Explanation:

#log_(3)81# is the same thing as writing #3^x = 81#, where you have to solve for #x#. #3# is the base number.

#3 * 3 * 3 * 3# is #81#, proving #3^4 = 81#. So, #4# is the answer.