How do you evaluate #n(m+(abs(-1))-n# when m=1, n=-6? Prealgebra Negative Numbers and Absolute Value Absolute Value 1 Answer Shwetank Mauria Nov 23, 2016 #n(m+(|-1|)-n=-6#, when #m=1# and #n=-6# Explanation: Value of #n(m+(|-1|)-n#, when #m=1# and #n=-6# can be obtained by substituting these values. #n(m+(|-1|)-n# = #(-6)(1+(|-1|)-(-6)# = #(-6)(1+1)-(-6)# = #(-6)*2+6# = #-12+6=-6# Answer link Related questions What is the value of the following expression?: #17 + 3*|4-8|-2# By how much would the value of the following expression change if the absolute value parenthesis... By how much would the value of the following expression change if the absolute value parenthesis... Can two different numbers have the same absolute value? How do you find the absolute value of #abs(10)#? How do you find the absolute value of #abs(-8)#? How do you find the absolute value of #abs(0)#? How do you evaluate #abs(-1-2)#? How do you evaluate #9div abs3#? How do you evaluate #abs(1-4)times-2#? See all questions in Absolute Value Impact of this question 1980 views around the world You can reuse this answer Creative Commons License