Question

How do you evaluate `sec((11pi)/2)`?

Answer 1

undefined infinity

Explanation:

`sec ((11pi)/2) = 1/cos ((11p)/2)`
`cos ((11pi)/2) = cos ((3pi)/2 + (8pi)/2) = cos ((3pi)/2 + 4pi) =`
`= cos ((3pi)/2) = 0`
Finally:
`sec ((11pi)/2) = 1/(cos) = 1/0`--> undefined infinity