How do you evaluate $sin ((-5pi)/6)$ ?

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Answer 1 · 2016-10-28T13:53:30

$sin(-(5pi)/6)=-1/2$

As $sin(-theta)=-sintheta$ and $sin(pi-theta)=sintheta$

$sin(-(5pi)/6)=-sin((5pi)/6)$

= $-sin((6pi-pi)/6)=-sin(pi-pi/6)$

= $-sin(pi/6)$

= $-1/2$

How do you evaluate sin ((-5pi)/6)sin ((-5pi)/6)?