How do you evaluate #sqrt(b^2-4ac)# for a=-9, b=10, c=-1?

1 Answer
Jul 19, 2017

Answer:

See a solution process below:

Explanation:

To evaluate this expression substitute:

#color(red)(-9)# for #color(red)(a)#

#color(blue)(10)# for #color(blue)(b)#

#color(green)(-1)# for #color(green)(c)#

#sqrt(color(blue)(b)^2 - 4color(red)(a)color(green)(c))# becomes:

#sqrt(color(blue)(10)^2 - (4 * color(red)(-9) * color(green)(-1))) =>#

#sqrt(100 - 36) =>#

#sqrt(64) =>#

#8#