# How do you solve #\sqrt { ( x - 2) ( x + 4) } - x - 2= 0#?

##### 2 Answers

No solutions

#### Explanation:

writing

by squaring we get

or

This fulfilles not our equation since

Move values that are not under the radical to the other side and square both sides. After Rearranging, you will find

#### Explanation:

First, move the values that aren't under the radical to the Right Hand Side (RHS):

Next, we'll FOIL the two expressions that are under the radical:

Next, we'll square both sides to get rid of the radical:

We can eliminate the

Finally, divide both sides by

Let's apply this back in the (somewhat) original equation:

Now, here's a tricky part. The square root of a number can be either positive or negative, since any **real** number squared is ALWAYS positive.