# How do you solve #\sqrt { ( x - 2) ( x + 4) } - x - 2= 0#?

##### 2 Answers

#### Answer:

No solutions

#### Explanation:

writing

by squaring we get

or

This fulfilles not our equation since

#### Answer:

Move values that are not under the radical to the other side and square both sides. After Rearranging, you will find

#### Explanation:

First, move the values that aren't under the radical to the Right Hand Side (RHS):

Next, we'll FOIL the two expressions that are under the radical:

Next, we'll square both sides to get rid of the radical:

We can eliminate the

Finally, divide both sides by

Let's apply this back in the (somewhat) original equation:

Now, here's a tricky part. The square root of a number can be either positive or negative, since any **real** number squared is ALWAYS positive.