Question

How do you evaluate `tan300`?

Answer 1

`tan300^o=-sqrt3`

Explanation:

It is presumed that by `tan300` it is meant to be `tan300^o`.

As adding or subtracting multiples of `2pi` radians or `360^o` does not change the trigonometric ratio

`tan300^o=tan(360^o-60^o)=tan(-60^o)`

Further as `tan(-theta)=-tantheta`

`tan300^o=tan(-60^o)=-tan60^o=-sqrt3`