# How do you evaluate the expression [(1/3)^-2]^3 using the properties?

${3}^{6}$
${\left[{\left(\frac{1}{3}\right)}^{-} 2\right]}^{3}$
${\left(\frac{1}{3}\right)}^{- 2 \cdot 3} = {\left(\frac{1}{3}\right)}^{-} 6 = {\left({1}^{1} / {3}^{1}\right)}^{-} 6 = {\left({1}^{1}\right)}^{-} \frac{6}{{3}^{1}} ^ - 6$
$= {1}^{-} \frac{6}{3} ^ - 6 = \frac{\frac{1}{1} ^ 6}{\frac{1}{3} ^ 6} = 1 \cdot {3}^{6} / 1 = {3}^{6}$