How do you evaluate the integral intx^10-6x^5+2x^3 dx? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer sjc Jun 28, 2018 x^11/11-x^6+x^4/2+c Explanation: using the power rule intx^ndx=x^(n+1)/(n+1)+c,x!=-1 int(x^10-6x^5+2x^3)dx =x^11/11-(6x^6)/6+(2x^4)/4+c cancelling down we have x^11/11-x^6+x^4/2+c Answer link Related questions How do you evaluate the integral intx^3+4x^2+5 dx? How do you evaluate the integral int(1+x)^2 dx? How do you evaluate the integral int8x+3 dx? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of |x|? What is the integral of 3x? What is the integral of 4x^3? What is the integral of sqrt(1-x^2)? What is the integral of sqrt(9-x^2)? See all questions in Integrals of Polynomial functions Impact of this question 5117 views around the world You can reuse this answer Creative Commons License