How do you evaluate the integral intx^10-6x^5+2x^3 dx?

1 Answer
Jun 28, 2018

x^11/11-x^6+x^4/2+c

Explanation:

using the power rule

intx^ndx=x^(n+1)/(n+1)+c,x!=-1

int(x^10-6x^5+2x^3)dx

=x^11/11-(6x^6)/6+(2x^4)/4+c

cancelling down we have

x^11/11-x^6+x^4/2+c