# How do you evaluate the integral intx^10-6x^5+2x^3 dx?

Jun 28, 2018

${x}^{11} / 11 - {x}^{6} + {x}^{4} / 2 + c$

#### Explanation:

using the power rule

$\int {x}^{n} \mathrm{dx} = {x}^{n + 1} / \left(n + 1\right) + c , x \ne - 1$

$\int \left({x}^{10} - 6 {x}^{5} + 2 {x}^{3}\right) \mathrm{dx}$

$= {x}^{11} / 11 - \frac{6 {x}^{6}}{6} + \frac{2 {x}^{4}}{4} + c$

cancelling down we have

${x}^{11} / 11 - {x}^{6} + {x}^{4} / 2 + c$