Question

How do you evaluate the integral `intx^10-6x^5+2x^3 dx`?

Answer 1

`x^11/11-x^6+x^4/2+c`

Explanation:

using the power rule

`intx^ndx=x^(n+1)/(n+1)+c,x!=-1`

`int(x^10-6x^5+2x^3)dx`

`=x^11/11-(6x^6)/6+(2x^4)/4+c`

cancelling down we have

`x^11/11-x^6+x^4/2+c`