What is the integral of #4x^3#?

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Answer 1 · 2018-03-11T19:43:38

The integral equals #x^4 + C#

As given by the power rule, #int x^ndx = x^(n + 1)/(n + 1)#.

#I = 4x^(3+ 1)/(3 + 1) = x^4 + C#

Hopefully this helps!

Answer 2 · 2018-03-11T19:45:47

#\int 4x^3 dx= x^4 + C#

#\int 4x^3 dx#

#=4(x^(3+1)/(3+1))+C# ; #C\equiv# arbitrary constant

#=4(x^(4)/(4))+C#

#= x^4 + C#