What is the integral of #sqrt(1-x^2)#?

1 Answer
Dec 18, 2014

Hint: First, apply trigonometric substitution. This question is in the form #sqrt(a^2-x^2)#. So you let x = a sinx (a in this case is 1) then take the derivative of x. Plug it back in the question #int sqrt(1-x^2) dx#
You will have to use the half-angle identity after.
Integrate. You will get an indefinite integral.
Set up a right triangle to find the value for the indefinite integral.

I hope this video would help clear things up.