Question

How do you evaluate the limit of `lim (-4x^2+2x-5)` as `x->2`?

Answer 1

Substitution. Answer `-17`

Explanation:

Question: Evaluate `lim_(x->2)(-4x^2+2x-5)`

By substitution, we get:
`lim_(x->2)(-4x^2+2x-5)`

`=-4(2^2)+2(2)-5`

`=-17`