# How do you evaluate the limit of lim (-4x^2+2x-5) as x->2?

May 13, 2017

Substitution. Answer $- 17$

#### Explanation:

Question: Evaluate ${\lim}_{x \to 2} \left(- 4 {x}^{2} + 2 x - 5\right)$

By substitution, we get:
${\lim}_{x \to 2} \left(- 4 {x}^{2} + 2 x - 5\right)$

$= - 4 \left({2}^{2}\right) + 2 \left(2\right) - 5$

$= - 17$