Question

How do you expand the binomial `(x-2)^3`?

Answer 1

`(x-2)^3 =x^3-6x^2+12x-8`

Explanation:

`(x-2)^3 =x^3+(""_1^3)x^2(-2)+(""_2^3)x(-2)^2+(-2^3)`

`(""_1^3)=(3*2*1)/2=3`
`(""_2^3)=(3*2*1)/2=3`
You can also use Pascal's triangle
So the answer is
`(x-2)^3 =x^3-6x^2+12x-8`