# How do you expand the binomial (x-2)^3?

Oct 16, 2016

${\left(x - 2\right)}^{3} = {x}^{3} - 6 {x}^{2} + 12 x - 8$

#### Explanation:

${\left(x - 2\right)}^{3} = {x}^{3} + \left({\text{_1^3)x^2(-2)+(}}_{2}^{3}\right) x {\left(- 2\right)}^{2} + \left(- {2}^{3}\right)$

(""_1^3)=(3*2*1)/2=3
(""_2^3)=(3*2*1)/2=3
You can also use Pascal's triangle
${\left(x - 2\right)}^{3} = {x}^{3} - 6 {x}^{2} + 12 x - 8$