Question

How do you expand the binomial `(x-2)^3` using the binomial theorem?

Answer 1

`=x^3-6x^2+12x-8`

Explanation:

Use the binomial expansion or Pascal's triangle(1 3 3 1)
`(x-2)^3=x^3+³C₁x^2(-2)+³C₂x(-2)^2+(-2)^3`
`=x^3-3*2*x^2+3*4*x-8`
`=x^3-6x^2+12x-8`