How do you express #1/(s+1)^2# in partial fractions?

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Answer 1 · 2016-05-07T10:25:41

#1/(s+1)^2# is already in its partial fractions form.

Partial fractions of #1/(s+1)^2# will be of type

#1/(s+1)^2=A/(s+1)+B/(s+1)^2#

= #(A(s+1)+B)/(s+a)^2#

or #1/(s+1)^2=(As+A+B)/(s+a)^2#

Equating coefficients of numerator, we have #A=0# and #A+B=1# or #B=1#.

Hence #1/(s+1)^2=0/(s+1)+1/(s+1)^2#

or #1/(s+1)^2=1/(s+1)^2#

It is apparent that #1/(s+1)^2# is already in its partial fractions form.