How do you express $cos^3theta+tan^2theta$ in terms of non-exponential trigonometric functions?

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Answer 1 · 2016-08-30T03:31:15

$cos^3theta+tan^2theta$

$=cos^3theta+(2sin^2theta)/(2cos^2theta)$

$=1/4(cos3theta+3costheta)+(1-cos2theta)/(1+cos2theta)$

How do you express cos^3theta+tan^2theta cos^3theta+tan^2theta in terms of non-exponential trigonometric functions?