How do you express #cos(pi/ 2 ) * cos (( 11 pi) / 6 ) # without using products of trigonometric functions?

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Answer 1 · 2016-06-22T10:23:03

#cos(pi/2)*cos((11pi)/6)=color(green)(0)#

#cos(pi/2)=0#
and anything multiplied by #0# is #0#

Answer 2 · 2016-06-22T10:26:13

Answer#=0.#

Using the value#cos(pi/2)=0,# we get the answer #0.#