Question

How do you express `cos(pi/ 3 ) * sin( ( pi) / 6 )` without using products of trigonometric functions?

Answer 1

`(1/4)`

Explanation:

`y = cos (pi/3).sin (pi/6)`
Trig table --> `cos (pi/3) = 1/2.` and `sin (pi/6) = 1/2`
Therefor, y can be expressed as: `y = (1/2)(1/2) = 1/4`