Question

How do you express `sin(pi/12) * cos(pi/3 )` without products of trigonometric functions?

Answer 1

`(1/2)sin (pi/12)`

Explanation:

`P = sin (pi/12).cos (pi/3)`
Trig table --> `cos (pi/3) = 1/2`
Therefor, P can be expressed as:
`P = (1/2)sin (pi/6)`
If required, we can find P by evaluating `sin (pi/12).` Use the trig identity:
`cos (pi/6) = sqrt3/2 = 1 - 2sin^2 (pi/12)`