# How do you express (x^2 - 4) / (x -1) in partial fractions?

Jul 18, 2016

$\frac{{x}^{2} - 4}{x - 1} = x + 1 - \frac{3}{x - 1}$

#### Explanation:

$\frac{{x}^{2} - 4}{x - 1}$

= $\frac{{x}^{2} - 1 - 3}{x - 1}$

= $\frac{{x}^{2} - 1}{x - 1} - \frac{3}{x - 1}$

= $\frac{\left(x - 1\right) \left(x + 1\right)}{x - 1} - \frac{3}{x - 1}$

= $x + 1 - \frac{3}{x - 1}$