How do you factor $1029yx^3 + 24y^4$ ?

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Answer 1 · 2015-05-12T14:09:12

$1029yx^3+24y^4=3y(343x^3+8y^3)$

$=3y((7x)^3+(2y)^3)$

$=3y(7x+2y)((7x)^2-(7x)(2y)+(2y)^2)$

$=3y(7x+2y)(49x^2-14xy+4y^2)$

using $a^3+b^3 = (a+b)(a^2-ab+b^2)$

There are linear factors of $(49x^2-14xy+2y^2)$ , but they have Complex coefficients.

How do you factor 1029yx^3 + 24y^41029yx^3 + 24y^4?