How do you factor #10m^3n^2-15m^2n+25m#?

1 Answer
May 10, 2015

#10m^3n^2-15m^2n+25m = 5m(2m^2n^2-3mn+5)#

To see that this does not factor further, let #p=mn#.

Then #2m^2n^2-3mn+5=2p^2-3p+5#

If this had linear factors, then it would factorise as #(2p-1)(p-5)# or #(2p-5)(p-1)# in order to get the coefficient of #p^2# and the constant term correct. Neither of these works.