# How do you factor 10q^3-1210q?

$10 q \left(q + 11\right) \left(q - 11\right)$

#### Explanation:

We can start by factoring out the 10 and a $q$:

$10 {q}^{3} - 1210 q$

$10 q \left({q}^{2} - 121\right)$

Notice that the statement within the brackets is of the form $\left({a}^{2} - {b}^{2}\right)$, meaning we can factor it into $\left(a + b\right) \left(a - b\right)$:

$10 q \left(q + 11\right) \left(q - 11\right)$