How do you factor #10x^2 + 16x - 55x - 88#?

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Answer 1 · 2016-06-17T20:32:50

#(5x + 8)(2x -11)#

Group the four terms into twp groups.

#(10x^2 + 16x) + (-55x -88)#

#2x(5x +8) -11(5x + 8) " take out common factors"#

#(5x + 8)(2x -11) " common bracket as a factor"#

Answer 2 · 2016-06-17T20:35:19

#(5x+8)(2x+1)#

In the given polynomial we recognize having #2x# as common factor between #10x^2 and 16x#
Hence, #10x^2+16x=2x(5x+8)#

#-11#is the common factor of #-55x and -88#

#-55x-88=-11(5x+8)#

#10x^2+16x-55x-88#
#=2x(5x+8)-11(5x+8)#
Taking the common factor #5x+8#

#=(5x+8)(2x-11)#