# How do you factor 10x^3-270?

$= 10 \left(x - 3\right) \left({x}^{2} + 3 x + 9\right)$
$10 \left({x}^{3} - 27\right) \text{ difference of cubes}$
$= 10 \left(x - 3\right) \left({x}^{2} + 3 x + 9\right)$