How do you factor #10z^2-17z+3#?
Given that the constant term is positive and the middle term is negative, I was looking for a factorization like
Of course there might have been a solution of the form
Factor y = 10x^2 - 17x + 3 = (x -p)(x - q). I use the new AC Method.
Converted trinomial: x^2 - 17x + 3 = (x - p')(x - q')
Compose factor pairs of a.c = 30 -> (1, 30)(2, 15)> This last sum is 17 = -b. Then p' = -2 and q' = -15.
Next: p = p'/2 = -2/10 = -1/5, and q = q'/2 = -15/10 = -3/2
Factored form: y = (x - 1/5)(x - 3/2) = (5x - 1)(2x - 3).