Question

How do you factor `125y^3z - z`?

Answer 1

It is

`125y^3z-z=z*(125y^3-1)=z*((5y)^3-1)=z*(5y-1)*(25y^2+5y+1)`

We used the identity

`a^3-1=(a-1)*(a^2+a+1)`