How do you factor #12a^2 - 4ac + 3ab - bc#? Algebra Polynomials and Factoring Factoring Completely 1 Answer George C. May 12, 2015 Let us try grouping and spotting common factors: #12a^2 - 4ac + 3ab - bc = (12a^2 - 4ac) + (3ab - bc)# #= (4a*3a - 4a*c) + (b*3a - b*c)# #= 4a(3a-c) + b(3a-c)# #= (4a + b)(3a - c)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1902 views around the world You can reuse this answer Creative Commons License